Find the square root of 3+4i
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Answered by
7
let x + iy be square root of (3 - 4i)
(x + iy)2 = 3 - 4i
x2 - y2 + 2xyi = 3 - 4i
on comparing
x2 - y2 = 3 -----(1)
2xy = -4
we have
(x2 + y2)2 = (x2 - y2)2 + (2xy)2
(x2 + y2)2 = 9 + 16
x2 + y2 = 5 ------(2)
from (1) and (2)
x = +- 2
y = +-1
Check by putting which combination satisfies.
Square root of (3 - 4i) is (+-2 -+i)
ie, (2 - i) and (-2 + i)
cristal:
thanks
Answered by
2
=> ✓3+✓4
=> ✓3 +2
This is your answer
=> ✓3 +2
This is your answer
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