find the square root of
(3a-2b-5c)
Answers
Answered by
1
Answer:
(3a+2b+3c)^2-(2a+3b+2c)^2+5b^2
=(5a+5b+5c)(a-b+c)+5b^2
=5a^2-5ab+5ac+5ab-5b^2+5bc+5ac-5bc+5c^2+5b^2
=5(a^2+2ac+c^2)
=5(a+c)^2
square root=root5(a+c)
Explanation:
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Answered by
0
Explanation:
ANSWER
(3a−2b−5c)
2
=(3a)
2
+(−2b)
2
+(−5c)
2
+(2×3a×−2b+2×(−2b)×(−5c)+2×−5c×3a)
=9a
2
+4b
2
+25c
2
−12ab+20bc−30ac
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