Find the Square root of 3x^2-8x+4√3
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Answer:
Given quadratic equation = √3x² - 8x + 4√3 = 0
We should factorize the equation first.
=√3x²-6x-2x+4√3 = 0
= √3x(x-2√3)-2(x-2√3) = 0
= (√3x-2) (x-2√3) = 0
= (√3x-2) = 0 , (x-2√3) = 0
= x = 2/√3 , x = 2√3.
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