Question

find the square root of -48-14i​

Answer 1

Answer:

not understand

Step-by-step explanation:

write again the question

Answer 2

Answer:

(a±bi) ²=(a²-b²) ±2abi

therefore,

a±bi=±√[(a²-b²) ±2abi]

±√(-48-14i) =±√(1-49-14i) =±√[(7i) ²+1²-2×7i]=

=±√(7i-1) ²=±(7i-1)