Question

Find the square root of 49 by successive subtraction

Answer 1

The solution goes.

1) 49 - 1 = 48
2) 48 - 3 = 45
3) 45 - 5 = 40
4) 40 - 7 = 33
5) 33 - 9 = 24
6) 24 - 11 = 13
7) 13 - 13 = 0

As you can see that given number 49 was repeatedly subtracted by successive odd numbers (starting from 1) and we get zero in the seventh step.
Therefore 7 is the square root of 49
Or we can also write it as:

$\sqrt{49 = 7}$

Answer 2

Formula:

subtract the odd number 1, 3, 5, 7, successively from the given number till we get zero

Step-by-step explanation:

49:

1. 49-1=48
2. 48-3=45
3. 45-5=40
4. 40-7=33
5. 33-9=24
6. 24-11=13
7. 13-13=0

after repeatingly subtracting 49 from successive odd numbers (from 1 ) in the seventh step we got zero.

Hence, 49 = 7 square

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