Math, asked by nidhep, 2 months ago

Find the square root of 4x^2 +2 +1/4x^2 pls I need fast

Answers

Answered by sandeepmaurya997
2

Step-by-step explanation:

16x^4+8x^2+1=0

16x^4+(4+4)x^2+1=0

16x^4+4x^2+4x^2+1=0

4x^2(4x^2+1)+1(4x^2+1)=0

(4x^2+1)(4x^2+1)=0

(4x^2+1)=0

4x^2= -1

x^2=(-1/4)

x=✓(-1/4).

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