Math, asked by cavin4980, 11 months ago

Find the square root of -5 + 12 i

Answers

Answered by jadhavvaishnavi867
1

Answer:

[√-5+12 i] = ?

Let, √-5+12 i = x + iy

x=2 & y=3

The square root of -5+12 i = 2+3 i

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Answered by xarthpanda
0

Let the root of the given expression be

√(-5 + 12i) = √p - i√q

where p,q > 0

 \sqrt{ - 5  + 12i}  =  \sqrt{p}   - i \sqrt{q}  \\ squaring \: both \: sides \\  - 5 + 12i = p - q +i 2 \sqrt{pq}   \\ comparing \: both \: sides \\  - 5 = p - q \:   and \: 12 = 2 \sqrt{pq} \\  =  >p = q - 5 \: and \: 36  = pq \\  =  > 36 = (q - 5)q  \:  =  >   {q}^{2}   - 5q - 36 = 0 \\  =  > (q + 4)(q - 9) = 0 \:   \\ =  > q =  - 4 \: and \: 9  \:   ,but \: q > 0 \: , so \: q = 9\\ =  > p =    4  \\\\

Therefore, √(-5+12i) = √4 - i√9

= 2 - 3i

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