Question

Find the square root of 6 into 1/3 up to three places of decimals.

Answer 1

Answer:

don't know if it is correct or not

Here you go:

We know that. 1^2 = 1 and 2^2 =4.

This implies that the square root x of 3 should be such that

1 < x < 2. So, let 3^0.5 = ( 2 - h)

where 0 < h < 1. => (2 - h)^2 = 3 => 4 -4h +h^2 = 3 => -4h < 3 - 4 ignoring h^2.