find the square root of 625y^20/144x^6z^2
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Answer:✒ 625y²⁰/ 144x⁶z²
✒ 625y²⁰/ 144x⁶z²✒ √625y²⁰/ √144x⁶z²
✒ 625y²⁰/ 144x⁶z²✒ √625y²⁰/ √144x⁶z²✒ 25y²⁰/ 12x⁶z²
4 Find the equation of the circle with centre $(1 , 1)$ and radius $\sqrt{2}$ ... ^2 = 36 - 16\\ = b = 20$ $\\$ Thus, the equation of the ellipse is $ \ dfrac{x^2}{6^2}+\dfrac{y^2}{(\sqrt{20})^2}=1$ ...2 a+3 6 —2c. 20. 5 a + i 6 + 11c. 21. 3a—7 6 + llc. 22. 61 6 — 2 c □*- 20 a. 23. ... For the square of a he used aa, which later became a 2 . ... To solve equations is to find their roots.
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Answer:
25y^20/12x^6z^2
Step-by-step explanation:
√625y^20/√144x^6z^2=25y^20/12x^6z^2
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