Question

Find the square root of complex number 1) -8-6i​

Answer 1

Answer:

√-8-6i=a+in

taking square on both side

(√-8-6i)^2=(a+ib)^2

-8-6i=a^2+2aib-b^2

I is consul

-8i-6=a^2+2ab-b^2

it not appropriate I think it helps you little bits

Answer 2

see in attachment

hope it's helps you ❤️