Question

find the square root of complex number 3+4i

don't tell anything for points
if correct i will add to brainlist​

Answer 1

Answer:

well nice question

Let the square root of 3 + 4i be x + iy.

So (x + iy) (x +iy) = 3 +4i

=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i

=> x^2 – y^2 + 2xyi = 3 + 4i

Equate the real and complex terms

=> x^2 - y^2 = 3 and 2xy = 4

2xy = 4

=> xy = 2

=> x = 2/y

Substitute in

=> x^2 -...

Answer 2

Step-by-step explanation:

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