find the square root of complex number 89 - 20√11 i
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Answer:
89-20√11i
=100-11-20√11i
=(10)^2-20√11i-11
=(10)^2-2.10.√11i+(11i)^2
=(10-11i)^2
so square root of 89-20√11i is
(10-11i)
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