Math, asked by meghnanaidu05, 6 hours ago

find the square root of each of the following by prime factorisation: of 9,36,484,900,4225,3969,5184,8100.​

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Answers

Answered by bhoomikab460
0

Answer:

9 = 3

36 = 6

484 = 22

900=30

4225=65

3969=63

5184=72

8100=90

Answered by abhinavmike85
28

Step-by-step explanation:

 \sqrt{9}   =  \sqrt{3 \times 3}  = 3 \\  \\  \sqrt{36}  =  \sqrt{2 \times 2 \times 3 \times 3}  = 2 \times 3 = 6 \\  \\  \sqrt{484}  =  \sqrt{2 \times 2 \times 11 \times 11}  = 2 \times 11 = 22 \\  \\  \sqrt{900}  =  \sqrt{2 \times 2 \times 3 \times 3 \times 5 \times 5}  = 2 \times 3 \times 5 = 30 \\  \\  \sqrt{4225} =  \sqrt{5 \times 5 \times 13 \times 13}  = 5 \times 13 = 65 \\  \\  \sqrt{3969}  =  \sqrt{3 \times 3 \times 3 \times 3 \times 7 \times 7}  = 3 \times 3 \times 7 = 63 \\  \\  \sqrt{5184}  =  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3}  = 2 \times 2 \times 2 \times 3 \times 3 = 72 \\  \\  \sqrt{8100}  =  \sqrt{2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 5 \times 5}  = 2 \times 3 \times 3 \times 5 = 90

Hope it helps

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