Math, asked by kavita51920, 11 months ago

Find the square root of following​

Attachments:

sivaprasath: 1) √3 + √2 2) 3 + √2
kavita51920: but how

Answers

Answered by ayushikumari18
0

√5+2√6

7×6

42

√11+6√2

17×2

34


kavita51920: answer is wrong
Answered by sivaprasath
0

Answer:

(i) \sqrt{3} + \sqrt{2}

(ii) 3 + \sqrt{2}

Step-by-step explanation:

Given :

To factorize :

(i) \sqrt{5+2\sqrt{6} },

(ii) \sqrt{11+6\sqrt{2} }

Solution :

We know that,

(a + b)² = a² + b² + 2ab,

Hence,.

(i) \sqrt{5+2\sqrt{6} }

\sqrt{5+2\sqrt{6} }

\sqrt{3 + 2 +2(\sqrt{3})(\sqrt{2})}

\sqrt{(\sqrt{3})^2 + (\sqrt{2})^2 +2(\sqrt{3})(\sqrt{2})}

\sqrt{(\sqrt{3}+\sqrt{2})^2}= \sqrt{3} + \sqrt{2}

(ii) \sqrt{11+6\sqrt{2} }

\sqrt{11+6\sqrt{2} }

\sqrt{9 + 2 +2(3)(\sqrt{2})}

\sqrt{(3)^2 + (\sqrt{2})^2 +2(3)(\sqrt{2})}

\sqrt{(3+\sqrt{2})^2}= 3 + \sqrt{2}

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