find the square root of following numbers by seq succesive subtraction:
1. 49
2. 121
3. 64
4. 169
Answers
Answered by
13
Answer:
(I)..49-1=48
48-3=45
45-5=40
40-7=33
33-9=26
26-11=15
15-15=0
We subtracted seven time to get 0
So, √49=7
(2)121-1=120
120-3=117
117-5=112
112-7=105
105-9=96
96-11=85
85-13=72
72-15=57
57-17=40
40-19=21
21-21=0
hence,we subtracted 11 times to get 0
So,√121=11
(3)64-1=63
63-3=60
60-5=55
55-7=48
48-9=39
39-11=28
28-13=15
15-15=0
Hence, we subtracted 8 times to get 0
So,√64=8
(4)169-1=168
168-3=165
165-5=160
160-7=153
153-9=144
144-11=133
133-13=120
120-15=105
105-17=88
88-19=69
69-21=48
48-23=25
25-25=0
Hence,we subtracted 13 times to get 0
So,√169=13
Answered by
5
Answer:
49- 1 = 48
121-1 = 120
64-1=63
169-1= 168
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