Question

Find the square root of
$(4 {a}^{2} + {b}^{2} + {c}^{2} + 4ab - 2bc - 4ac )$
​

Answer 1

Sqrt((4a)^2 + (b)^2 + (c)^2 + 4*a*b - 2*b*c - 4*a*c)

= sqrt((- 2a - b + c)^2)

= - 2a - b + c ——> Answer

Answer 2

ANSWER

$4 {a}^{2} + {b}^{2} + {c}^{2} + 4ab - 2bc - 4ac \\ \\ {(2a)}^{2} + {b}^{2} + {c}^{2} + 2(2a)(b) + 2(b)( - c) + 2(2a)( - c) \\ \\ {(2a + b - c)}^{2} .... |answer| \\ \\ whose \: square \: root \: is \\ \\ 2a + b - c$

ANSWER BY...

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