Math, asked by Saby123, 10 months ago

Find the Square root of :

 \sqrt{(x - y)(y - z)}  +  \sqrt{(y - z)(x - z)}  +  \sqrt{(z - x)(x - y)}

Answers

Answered by rohit301486
5

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{ \sqrt{( {x}^{2}  +  {y}^{2}  -  {z}^{2} - 3xy + xz + yz })  }}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{Given :}}

\tt: \implies \sqrt{(x - y)(y - z)} + \sqrt{(y - z)(x - z)} + \sqrt{(z - x)(x - y)}

\red{\underline \bold{To \: Find :}}

\tt: \implies the \: square \: root

  • Given Question

\tt: \implies \: squaring - both \: sides

\tt: \implies\bigg[(x - y) \: (y - z)\bigg] + \bigg[(y - z) \: (x - z)\bigg] + \bigg[(z - x) \: (x - y)\bigg]

\tt: \implies xy - zx -  {y}^{2}  + yz + xy - zy - xz -  {z}^{2}  + xz - yz -  {x}^{2}  + xy

\tt: \implies -  {x}^{2}  -  {y}^{2}  +  {z}^{2}  + 3xy - xz - yz

\tt: \implies taking - square \: root - back

\green{\tt{\therefore{ \sqrt{( {x}^{2}  +  {y}^{2}  -  {z}^{2} - 3xy + xz + yz })  }}}

Answered by vkpathak2671
1

Step-by-step explanation:

The Square Root Calculator will find the square root of the number you enter. Number. Square Root. Related Topic How to calculate square roots without ...

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