find the square root of the complex number -1+2√2i
Answers
Answer:
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Step-by-step explanation:
form a%2Bbi is abs%28a%2Bbi%29=sqrt%28a%5E2%2Bb%5E2%29. Remember, absolute value geometrically is the distance from the origin. So in this case, we're finding the distance is from the point (a,b) to the origin (0,0) (in the complex plane)
Example:
Problem:
Find the absolute value of 3-6i.
Solution:
In this case, a=3 and b=-6
abs%28a%2Bbi%29=sqrt%28a%5E2%2Bb%5E2%29 Start with the given formula.
abs%283-6i%29=sqrt%28%283%29%5E2%2B%28-6%29%5E2%29 Plug in a=3 and b=-6
abs%283-6i%29=sqrt%289%2B36%29 Square 3 to get 9. Square -6 to get 36
abs%283-6i%29=sqrt%2845%29 Add
abs%283-6i%29=3%2Asqrt%285%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)
So the absolute value of 3-6i is 3%2Asqrt%285%29 which approximates to 6.708