find the square root of the complex number 3i
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Answer:
⇒3+4i=2+i
Step-by-step explanation:
Given, z=3+4i
(x+iy)2=3+4i
x2−y2+i(2xy)=3+4i
⇒x2−y2=3 and 2xy=4
⇒x2−y2=3 and xy=2
∴x=2 and y=1
⇒3+4i=2+i
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