find the square root of the following 42 correct to one place of decimal
i want step by step explanation
ans is 6.5
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Answer:
1) \sqrt42 = 6.4
4
2=6.4 (one place of decimal)
2) \sqrt67 = 8.185
6
7=8.185 (three places of decimal)
3) \sqrt346 = 18.60
3
46=18.60 (two places of decimal)
4) \sqrt395 = 19.874
3
95=19.874 (three places of decimal)
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