Find the square root of the following by successive subtraction. (a). 121 (b) 64
Answers
Answered by
2
a) 11 b) 8
Hope you found it simple
Hope you found it simple
anjuyadav456:
iska pura solution bata dijiye please Sir
121: 121-1= 120
120-3=117
117-5= 112
112-7=105
105-9= 96
96-11=85
85-13= 72
72-15= 57
57-17= 40
40-19= 21
21-21=0
120-3=117
117-5= 112
112-7=105
105-9= 96
96-11=85
85-13= 72
72-15= 57
57-17= 40
40-19= 21
21-21=0
Count the steps
And just subtract odd numbers from the result coming
Hope you found me if service
*of
Please mark me as brainiest
Will you please mark me as brainliest
Answered by
4
(a)121
1. 121 – 1 = 120
2. 120 – 3 = 117
3. 117 – 5 = 112
4. 112 – 7 = 105
5. 105 – 9 = 96
6. 96 – 11 = 85
7. 85 – 13 = 72
8. 72 – 15 = 57
9. 57 – 17 = 40
10. 40 – 19 = 21
11. 21-21=0
Thus, we have subtracted consecutive odd numbers from 121 starting from 1. 0 is obtained in the 11th step. So we have √121 = 11.
(b)64
1. 64-2=62
2. 62-4=58
3. 58-6=52
4. 52-8=44
5. 44-10=34
6. 34-12=22
7. 22-14=8
8. 8-8=0
Thus, we have subtracted consecutive even numbers from 64 starting from 2 to 0 is obtained in the 8th step.
So we have √64=8
Hope this will help u
@aryan tennyson
1. 121 – 1 = 120
2. 120 – 3 = 117
3. 117 – 5 = 112
4. 112 – 7 = 105
5. 105 – 9 = 96
6. 96 – 11 = 85
7. 85 – 13 = 72
8. 72 – 15 = 57
9. 57 – 17 = 40
10. 40 – 19 = 21
11. 21-21=0
Thus, we have subtracted consecutive odd numbers from 121 starting from 1. 0 is obtained in the 11th step. So we have √121 = 11.
(b)64
1. 64-2=62
2. 62-4=58
3. 58-6=52
4. 52-8=44
5. 44-10=34
6. 34-12=22
7. 22-14=8
8. 8-8=0
Thus, we have subtracted consecutive even numbers from 64 starting from 2 to 0 is obtained in the 8th step.
So we have √64=8
Hope this will help u
@aryan tennyson
Similar questions