Find the square root of the following numbers by repeated subtraction method
i) 9 ii)121 iii)225 iv)196
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Answer:
(i) 3
(ii) 11
(iii) 15
(iv) 14
Step-by-step explanation:
(i) 9-1=8
8-3 =5
5-5=0
then the root of 9 is 3
(ii) 121-1 =120
120-3=117
117-5=112
112-7=105
105-9=96
96-11=85
85-13=72
72-15=57
57-17=40
40-19=21
21-21=0
then the root of 121 is 11.
(iii) 225-1=224
224-3=221
221-5=216
216-7=209
209-9=200
200-11=189
189-13=176
176-15=161
161-17=144
144-19=125
125-21=104
104-23=81
81-25=56
56-27=29
29-29=0
then the root of 225 is 15
(iv) 196-1=195
195-3=192
192-5=187
187-7=180
180-9=171
171-11=160
160-13=147
147-15=132
132-17=115
115-19=96
96-21=75
75-23=52
52-25=27
27-27=0
then the root of 196 is14
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