Find the square root of the following numbers by the repeated subtraction method.
(1) 16
(11) 49
(II) 64
100
(v) 169
(vi) 81
(VI) 256
144
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Answer:
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(i) 64=2×2×2×2×2×2= 2
3
×2
3
=4
3
3
64
=4
(ii) 512=2×2×2×2×2×2×2×2×2×2×2×2
= 2
3
×2
3
×2
3
=8
3
3
512
=8
(iii) 10648= 2
3
×11
3
=22
3
3
10648
=22
(iv) 27000= 2
3
×3
3
×5
3
=30
3
3
27000
=30
(v) 15625= 5
3
×5
3
=25
3
3
15625
=25
(vi) 13824= 2
3
×2
3
×2
3
×3
3
=24
3
3
13824
=24
(vii) 110592= 2
3
×2
3
×2
3
×2
3
×3
3
=48
3
3
110592
=48
(viii) 46656= 2
3
×2
3
×3
3
×3
3
=36
3
3
46656
=36
(ix) 175616= 2
3
×2
3
×2
3
×7
3
=56
3
3
175616
=56
(x) 91125= 5
3
×3
3
×3
3
=45
3
3
91125
=45
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