find the square root of the following trinomial
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y=9
Step-by-step explanation:
it can also be writen as
y^2-18y+81=0
y^2 -9 y-9y+81=0
(taking y & 9 common respectively)
y(y-9)-9(y-9)=0
(y-9)(y-9)=0
y=9
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