Question

Find the square root of the following trinomials:
64 – 16y + y²
​

Answer 1

Answer:

8-4√y+y

I hope the answer is correct

Answer 2

Answer:

SOLUTION OF THE GIVEN QUESTION:-

$64 - 16y + {y}^{2} \\ = {8}^{2} - (2 \times 8 \times y) + {y}^{2} \\ = {(8 - y) }^{2} \: \: \: \: \: \: \: \: \: \: ....... {eq}^{n} (1) \\ now \: finding \: root \: of \: the \: {eq}^{n} (1) \\ \sqrt{ {(8 - y)}^{2} } \\ = \sqrt{(8 - y)(8 - y)} \\ = (8 - y)$