Math, asked by shubhamshukla12527, 10 months ago

find the square root of the fraction 81/121​

Answers

Answered by ammu6002
5

Answer:

9/11

Step-by-step explanation:

given ;81/121

to find;√(81/121)- (1)

we know that 81=9×9

=9^2

since 121=11×11

i.e=11^2

(1) - √(81/121)

we can write it as - √{(9^2)/(11^2)}

= 9/11

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Answered by Mihir1001
5
We have,

 \quad  \sqrt{ \frac{81}{121} }  \\  \\  =  \sqrt{ \frac{9 \times 9}{11 \times 11} }  \\  \\  =  \sqrt{ \frac{ {(9)}^{2} }{ {(11)}^{2} } }  \\  \\  =  \sqrt{ { \left(  \frac{9}{11} \right) }^{2} }  \\  \\  =   { \left(  \frac{9}{11} \right) }^{ \cancel{2} \times  \large{ \frac{1}{ \cancel{2}} }}  \\  \\  =  \frac{9}{11}
Hence,
 \\  \sqrt{ \frac{81}{121} }  =  \frac{9}{11}  \\
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