Question

find the square root of the smallest square that is divisible by 5,
14 and 21​

Answer 1

Answer:

Hey there!

Since, we wanted smallest perfect square number divisible by 6, 9 and 15.

So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

= 90 × 2 × 5

= 90 × 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900

SOLUTION IN THE ABOVE PIC. IS ALSO FOR REFERENCE

Step-by-step explanation:

Answer 2

Answer:

here is your answer

Step-by-step explanation:

Answer: If we want the smallest number divisible by 5 , 14 , 21 then we have to find out the LCM of 5 , 14 , 21 . Now we can write 5 = 1 × 5 14 = 2 × 7 21 = 3 × 7 Now LCM = 1 × 2 × 3 × 5 × 7 × 7 = 1470 Here we find the LCM using the concept that digits which is common in all.