Question

find the square root of the smallest square that is divisible by the number 5,14,21​

Answer 1

Step-by-step explanation:

form a%2Bbi is abs%28a%2Bbi%29=sqrt%28a%5E2%2Bb%5E2%29. Remember, absolute value geometrically is the distance from the origin. So in this case, we're finding the distance is from the point (a,b) to the origin (0,0) (in the complex plane)

Example:

Problem:

Find the absolute value of 3-6i.

Solution:

In this case, a=3 and b=-6

abs%28a%2Bbi%29=sqrt%28a%5E2%2Bb%5E2%29 Start with the given formula.

abs%283-6i%29=sqrt%28%283%29%5E2%2B%28-6%29%5E2%29 Plug in a=3 and b=-6

abs%283-6i%29=sqrt%289%2B36%29 Square 3 to get 9. Square -6 to get 36

abs%283-6i%29=sqrt%2845%29 Add

abs%283-6i%29=3%2Asqrt%285%29 Simplify the square root (note: If you need help with simplifying square roots, check out this solver)

So the absolute value of 3-6i is 3%2Asqrt%285%29 which approximates to 6.708