Find the square root of the smallest square that is divisible by the number 15, 14, 21
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Answer:
Since, we wanted smallest perfect square number divisible by 6, 9 and 15.
So, we calculated LCM by prime factorisation.
LCM = 90
But, 2 and 5 are not in pair.
Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).
= 90 × 2 × 5
= 90 × 10
= 900
Hence,
Required smallest square no. that's divisible by 6, 9 and 15 = 900
SOLUTION IN THE ABOVE PIC. IS ALSO FOR REFERENCE
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