Math, asked by maningh84, 11 months ago

Find the square root of the sum of cubes of first three natural numbers.​

Answers

Answered by pulakmath007
1

The square root of the sum of cubes of first three natural numbers = 6

Given :

First three natural numbers

To find :

The square root of the sum of cubes of first three natural numbers

Solution :

Step 1 of 3 :

Find first three natural numbers

First three natural numbers are 1 , 2 , 3

Step 2 of 3 :

Find sum of cubes of first three natural numbers

The sum of cubes of first three natural numbers

= 1³ + 2³ + 3³

= 1 + 8 + 27

= 36

Step 3 of 3 :

Find square root of the sum of cubes of first three natural numbers

The square root of the sum of cubes of first three natural numbers

= Square root of 36

 \sf =  \sqrt{36}

 \sf =  \sqrt{ {6}^{2} }

 =  \sf 6

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