Question

Find the square root of the sum of the cubes of first three natural number ​

Answer 1

1^3+2^3+3^3————————n^3=(1+2+3———————n^2)

ATQ=>(1+2+3)^2/2

=>(1+2+3)=>6

Answer 2

Answer:

Step-by-step explanation:

As we know that first three natural no. is 1, 2, and 3.

Cube of 1 is 1

Cube of 2 is 8

Cube of 3 is 27

Add all 1 , 8 and 27

1+8+27 = 36

Atq,

Square root of 36 is 6

Hence, 6 is the right answer.

I hope it will help you.