Question

find the square root of
(x^2+4x+4) (x^2+6x+9).

Answer 1

First, solving the equations

(x²+4x+4)(x²+6x+9)

=> [x²+2(2x) +2²] [x²+2(3x) +3²]

=> [(x+2)²(x+3)²]


Now, square root of (x+2)²(x+3)²


=> √[(x+2)(x+3)] ²

=> (x+2)(x+3)



I hope this will help you


(-:

Answer 2

Solution:-

given by :-

$( {x}^{2} + 4x + 4)( {x}^{2} + 6x + 9) \\ ( {x }^{2} + 2x + 2x + 4)( {x}^{2} + 3x + 3x + 9) \\ x(x + 2) + 2(x + 2) ( x(x + 3) + 3(x + 3)) \\ (x + 2)(x + 2)(x + 3)(x + 3) \\ {(x + 2)}^{2} ( {x + 3)}^{2} \\ square \: root \: of \\ \sqrt{ {(x + 2)(x + 3)}^{2} } \\ (x + 2)(x + 3)ans \\ \\ i \: hope \: it \: is \: helpfull \: for \: u$