Question

find the square root of x^4+1/x^4-2,pleaseeeeeeee​

Answer 1

Step-by-step explanation:

$= {x}^{4} + \frac{1}{ {x}^{4} } - 2 \\ = {x}^{4} + \frac{1}{ {x}^{4} } - 2 \times {x}^{2} \times \frac{1}{ {x}^{2} } \\ = { ({x}^{2}) }^{2} + { (\frac{1}{ {x}^{2} } )}^{2} - 2 \times {x}^{2} \times \frac{1}{ {x}^{2} } \\ = {( {x}^{2} - \frac{1}{ {x}^{2} } )}^{2} \\ now \: square \: root \\ = \sqrt{ {( {x}^{2} - \frac{1}{ {x}^{2} } )}^{2} } = {x}^{2} - \frac{1}{ {x}^{2} } answer..$

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