Question

find
the square root
the following
expression :
16x²+x-1​

Answer 1

Answer:

(i)  Given : 16x² =  24x + 1

16x² – 24x – 1 = 0

On comparing the given equation with,  ax² +  bx + c = 0

Here, a = 16 , b = - 24 , c = - 1

Discriminant , D = b² -  4ac

D = (-24)² - 4(16)(-1)

D = 576 + 64

D = 640

Since, D ≥ , 0 so given Quadratic equation has distinct real roots which are given by

x = [- b ± √D]/2a

x= −(−24) ±√640/ 2(16)

x =[ 24 ± 8√10] /32

x = 8 [3 ± √10]/32

x= (3 ± √10) /√4

x = (3 + √10) /√4  or x = (3 - √10) /√4

Hence, the Roots are (3 + √10) /√4  and x = (3 - √10) /√4.

Answer 2

Answer:

-1

Step-by-step explanation: