find the square roots of
-11 - 60√(-1)
Answers
Answered by
1
Answer:
Step-by-step explanation:
(-11-60√-1)^2
(-11-60×-1)^2
(-11+60)^2
49^2
2401
Answered by
3
Answer:±(5-6i)
Step-by-step explanation:
-11-60√-1 ⇒-11-60i [∴i²=-1]
let square root of -11-60i be in the form of x+yi
(x+yi)² = -11-60i
x²-y²+2xyi= -11-60i
x²-y²=-11 ............(1)
2xyi= -60i ⇒xy=-30 ⇒ y = -30/x ............(2)
put in equation 1
x²-()²= -11
x²-900/x² = -11
x^4-900 = -11x²
x^4+11x² -900 = 0
x^4+36x² - 25x² - 900 = 0
x²(x²+36) - 25(x²+36) = 0
(x²-25)(x²+36)=0
x²=25 ; x²= -36
x = ±5 ; x=±6i
y= ±6i ;y= ±5
answer : ±(5-6i)
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