find the square roots of 144 and 81 by the method of repeated subtraction
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44-1=143, 143-3=140, 140-5=135, 135-7=128, 128-9=119, 119-11=108, 108-13=95, 95-15=80, 80-17=63, 63-19=44, 44-21=23, 23-23=0, √144=12.
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Answer:
The square roots of 144 and 81 are 12 and 9 respectively.
Step-by-step explanation:
- By the property of square numbers, we can say that if a natural number is a square number, then it has to be the sum of successive odd numbers starting from 1.
- By using this property ,we can find out the square root of a number by repeated subtraction method.
- We can find the square root of a number by repeatedly subtracting successive odd numbers from the given square number, till we get zero.
144 - 1 = 143
143 - 3 = 140
140 - 5 = 135
135 - 7 = 128
128 - 9 = 119
119 - 11 = 108
108 - 13 = 95
95 - 15 = 80
80 - 17 = 63
63 - 19 = 44
44 - 21 = 23
23 - 23 = 0
As we can see that the last difference is zero, 144 is a perfect square.
As we have performed repeated subtraction 12 times, we can say that the square root of 144 is 12 . After the 12 the subtraction, we got the remainder zero.
Similarly,
81 - 1 = 80
80 - 3 = 77
77 - 5 = 72
72 - 7 = 65
65 - 9 = 56
56 - 11 = 45
45 - 13 = 32
32 - 15 = 17
17 - 17 = 0
Since the last difference is zero, 81 is a perfect square.
The square root of 81 is 9 as we have performed repeated subtraction 9 times. After the 9 the subtraction, we got the remainder zero.
For more examples of repeated subtraction method, click here ->
https://brainly.in/question/1224267
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