Math, asked by chibuikeugwuibe, 11 months ago

Find the square roots of the equation 3y2 + 25y - 18=0

Answers

Answered by amitkumar44481
1

Question :

Q. Find the square roots of the equation 3y²+ 25y - 18=0.

 \\ \\

Explanation :

We have equation,

3y²+25y-18=0.

3y²+27y-2y-18=0.

3y(y+9)-2(x+9)=0.

(3y-2)(x+9)=0

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Either,

y=2/3. and. x=-9.

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How to find middle terms,

[tex]

\begin{array}{r | l}

2 & 54 \\

\cline{2-2} 3 & 27 \\

\cline{2-2} 3 & 9 \\

\cline{2-2} 3 & 3 \\

\cline{2-2} 3 & 1

\end{array}

\\ [/tex]

Product be,

=> 3*3*3 =27.

=> 2.

It's means, 27y-2y= 25y.

 \\ \\

Therefore, the value of x = 2/3.

Answered by sanjaypatil101972
0

Answer:

We have equation,

3y²+25y-18=0.

3y²+27y-2y-18=0.

3y(y+9)-2(x+9)=0.

(3y-2)(x+9)=0

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