Find the square roots of the equation 3y2 + 25y - 18=0
Answers
Answered by
1
Question :
Q. Find the square roots of the equation 3y²+ 25y - 18=0.
Explanation :
We have equation,
3y²+25y-18=0.
3y²+27y-2y-18=0.
3y(y+9)-2(x+9)=0.
(3y-2)(x+9)=0
Either,
y=2/3. and. x=-9.
How to find middle terms,
[tex]
\begin{array}{r | l}
2 & 54 \\
\cline{2-2} 3 & 27 \\
\cline{2-2} 3 & 9 \\
\cline{2-2} 3 & 3 \\
\cline{2-2} 3 & 1
\end{array}
\\ [/tex]
Product be,
=> 3*3*3 =27.
=> 2.
It's means, 27y-2y= 25y.
Therefore, the value of x = 2/3.
Answered by
0
Answer:
We have equation,
3y²+25y-18=0.
3y²+27y-2y-18=0.
3y(y+9)-2(x+9)=0.
(3y-2)(x+9)=0
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