Math, asked by sarah4348, 11 months ago

Find the square roots of the following numbers by prime factorisation method:
(i) 1849 (ii) 4356 (iii) 6241
vi) 8836 (v)8281 (vi) 9025​

Answers

Answered by hardikpaneru04
8

Answer:

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Step-by-step explanation:

43) 1849(43

1849

------------

00

43 x 43 = 1849

2)4356 = 2 x 2 x 3 x 3 x 11 x 11

√4356 = √(2 x 2 x 3 x 3 x 11 x 11)

= 2 × 3 × 11

= 66

3)6241 = 79×79

= 79^2

now,

√6241 = √79^2 = 79

4)

8836/2=4418,

4418/2= 2209,

2209/47=47,

47/47=1

Answer is 2*47= 94

5)

√8281 = √(7 × 7 )× (13 × 13)

√8281 = 7 × 13

√8281 = 91

6) 9025 = 5 * 5 * 19 * 19

√(9025) = √(5 * 5 * 19 * 19 )

= 5 * 19

√(9025) = 95

Answered by afifanaaz98765
0

Step-by-step explanation:

Step-by-step explanation:

43) 1849(43

1849

00

43 x 43 = 1849

2)4356 = 2 x 2 x 3 x 3 x 11 x 11

√4356 = √(2 x 2 x 3 x 3 x 11 x 11)

= 2 × 3 × 11

= 66

3)624179x79

= 79^2

now,

√6241= √79^2 = 79

8836/2=4418,

4418/2=2209,

2209/47=47,

47/47=1

Answer is 2*47= 94

V 31

5)

√8281= √(7 x 7 )x (13 x 13)

√8281=7 x 13

√8281 = 91

6) 9025 = 5 * 5 * 19 * 19

√(9025)=√(5 * 5 * 19 * 19)

= 5 * 19

√(9025) = 95

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