Find the square roots of the following numbers by prime factorisation method:
(i) 1849 (ii) 4356 (iii) 6241
vi) 8836 (v)8281 (vi) 9025
Answers
Answer:
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Step-by-step explanation:
43) 1849(43
1849
------------
00
43 x 43 = 1849
2)4356 = 2 x 2 x 3 x 3 x 11 x 11
√4356 = √(2 x 2 x 3 x 3 x 11 x 11)
= 2 × 3 × 11
= 66
3)6241 = 79×79
= 79^2
now,
√6241 = √79^2 = 79
4)
8836/2=4418,
4418/2= 2209,
2209/47=47,
47/47=1
Answer is 2*47= 94
5)
√8281 = √(7 × 7 )× (13 × 13)
√8281 = 7 × 13
√8281 = 91
6) 9025 = 5 * 5 * 19 * 19
√(9025) = √(5 * 5 * 19 * 19 )
= 5 * 19
√(9025) = 95
Step-by-step explanation:
Step-by-step explanation:
43) 1849(43
1849
00
43 x 43 = 1849
2)4356 = 2 x 2 x 3 x 3 x 11 x 11
√4356 = √(2 x 2 x 3 x 3 x 11 x 11)
= 2 × 3 × 11
= 66
3)624179x79
= 79^2
now,
√6241= √79^2 = 79
8836/2=4418,
4418/2=2209,
2209/47=47,
47/47=1
Answer is 2*47= 94
V 31
5)
√8281= √(7 x 7 )x (13 x 13)
√8281=7 x 13
√8281 = 91
6) 9025 = 5 * 5 * 19 * 19
√(9025)=√(5 * 5 * 19 * 19)
= 5 * 19
√(9025) = 95