Question

find the square (x/4-y/3)^2 best ans in brainliest​

Answer 1

Hey friend!!!

Here is your answer..

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$( { \frac{x}{4} - \frac{y}{3} ) }^{2} \\ \\ \frac{ {x}^{2} }{16} + \frac{ {y}^{2} }{9} - 2 \times \frac{x}{4} \times \frac{y}{3} \\ \\ \frac{ {x}^{2} }{16} - \frac{ {y}^{2} }{9} - \frac{xy}{6}$

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Answer 2

By using formulae

(a - b)^2 = a^2. -- 2ab + b^2

here a = x/4 and b = y/3

= (x/4)^2. - 2 (x/4)(y/3) + (y/3)^2

= x^2/16 - xy/8 + y^2/9

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