Math, asked by muskandhillon, 7 hours ago

Find the squareroot of 100 by the method of repeated subraction?​

Answers

Answered by kumarraj1799
0

Step-by-step explanation:

100-1=99

99-3=96

96-5=91

91-7=84

84-9=75

75-11=64

64-13=51

51-15=36

36-17=19

19-19=0

There are total 10 numbers

So, 10 is the square root of 100

Answered by salman407ah
1

Answer:

Ncert solutions

Grade 8

Mathematics

Science

Chapters in NCERT Solutions - Mathematics , Class 8

Exercises in Squares and Square Roots

Question 3

Q3) Find the square roots of 100 and 169 by the method of repeated subtraction.

Solution

Transcript

Solution:

By successive subtracting odd natural numbers from 100,

100 – 1 = 99

99 – 3 = 96

96 – 5 = 91

91 – 7 = 84

84 – 9 = 75

75 – 11 = 64

64 – 13 = 51

51 – 15 = 36

36 – 17 = 19

19 – 19 = 0

This successive subtraction is completed in 10 steps.

Therefore \sqrt{100}=10

100

=10

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