find the squares by the identites
(3/2x+2/3y)²
Answers
Answered by
2
ANSWER
(2x+3y) 2
=(2x)
2
+2(2x)(3y)+(3y)
2
=4x
2
+12xy+9y
2
Aliter: (2x+3y)
2
=(2x+3y)(2x+3y)
=2x(2x+3y)+3y(2x+3y)
=(2x)(2x)+(2x)(3y)+(3y)(2x)+(3y)(3y)
=4x
2
+6xy+6yx+9y 2
[∵xy=yx]
(2x+3y) 2
=4x 2 +12xy+9y
Answered by
2
Answer:
(3/2x)^2+(2/3y)^2+2.3/2x.2/3y
9/4x^2+4/9y^2+ 12/6xy
9/4x^2+4/9y^2+2xy
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