Question

Find the squares for each of the following using the method of squaring a 2-digit number having units digit as 5. a 45 b 75 c95 d 25 e 65​

Answer 1

Answer:

$\huge\mathcal{\fcolorbox{lime}{pink}{\pink{ ❥solution✭࿐ }}}$

Step-by-step explanation:

If a normal distribution has a mean of 75 and a standard deviation of 10, 95% of the distribution can be found between which two values?

A) 0, 95

B) 65, 85

C) 55, 95

D) 45, 105

Answer: C. 95% of the distribution (area under the curve) is 1.96 standard deviations from the mean which can be estimated at 2.Therefore 75-20 = 55 is the lower value and 75+20 = 95 is the upper value.

If a normal distribution has a mean of 35 and a variance of 25, 68% of the distribution can be found between which two values?

A) 30, 40

B) 25, 45

C) 0, 70

D) 20, 50

Answer: A. 68% of the distribution (area under the curve) is about +/- 1 standard deviation from the mean. The standard deviation is the square root of the variance and therefore = 5. Therefore 35-5 = 30 is the lower value and 35+5 = 40 is the upper value.

A distribution of measurements for the length of widgets was found to have a mean of 92.0mm and a standard deviation of 2.50mm. Approximately what percent of measurements are between 87.00mm and 97.00mm?

A) 100%

B) 68%

C) 95%

D) 99%

Answer: C. The measurements of 87.00mm and 97.00mm are two standard deviations away from the mean of 92.00mm. Therefore about 95% of the values recorded are between 87.00mm and 97.00mm.

Hope it helps you..

Answer 2

Answer:

If a normal distribution has a mean of 75 and a standard deviation of 10, 95% of the distribution can be found between which two values?

A) 0, 95

B) 65, 85

C) 55, 95

D) 45, 105

Answer: C. 95% of the distribution (area under the curve) is 1.96 standard deviations from the mean which can be estimated at 2.Therefore 75-20 = 55 is the lower value and 75+20 = 95 is the upper value.

If a normal distribution has a mean of 35 and a variance of 25, 68% of the distribution can be found between which two values?

A) 30, 40

B) 25, 45

C) 0, 70

D) 20, 50

Answer: A. 68% of the distribution (area under the curve) is about +/- 1 standard deviation from the mean. The standard deviation is the square root of the variance and therefore = 5. Therefore 35-5 = 30 is the lower value and 35+5 = 40 is the upper value.

A distribution of measurements for the length of widgets was found to have a mean of 92.0mm and a standard deviation of 2.50mm. Approximately what percent of measurements are between 87.00mm and 97.00mm?

A) 100%

B) 68%

C) 95%

D) 99%

Answer: C. The measurements of 87.00mm and 97.00mm are two standard deviations away from the mean of 92.00mm. Therefore about 95% of the values recorded are between 87.00mm and 97.00mm.

Hope it helps you..