Math, asked by rs4486379, 6 months ago

find the squares of the first 10 natural numbers observe their units digits do you note​

Answers

Answered by Anonymous
3

Answer:

sum of squares of first natural numbers = 6

n(n+1)(2n+1)

Here, n= 10

sum =6

10(11)(21)

=5×11×7=385

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Answered by Anonymous
7

\fcolorbox{orange}{aqu}{Solution:}

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\tt{Sum \:of \:squares \:of \:first \:natural }\tt{numbers }

\tt{n}\tt\frac{(n+1)\:(2n+1)}{6}

\tt{Here, \:n\:=\:10}

\tt{∴\:Sum\:=}\tt\frac{10(11)(21)}{6}

\tt{5\:×\:11\:×\:7}

\tt{385}

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\sf\pink{Answer\: ↛}\mathtt\blue{385}

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