Find the squares of the following numbers using the identity (a – b)²
= a²
– 2ab + b²
(a) 98²
(b) 999²
(c) 495²
Answers
Answered by
4
Answer:let 98 as (100-2)²Step-by-step explanation:(100-2)²
=100²-2.100.2+2²
=10000-400+4
=10000-404 [400+4 BODMAS RULE]
=9596
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similarly you have to solve others numbers break them into two numbers and then put it in formula
hope i'll help you.....
Answered by
6
↓Identity used ↓
(a – b)² = a² – 2ab + b²
(a) 98²
(100 - 2)²
10000 + 4 - 400
9604
(b) 999²
(1000 - 1)²
(1000000 + 1 - 2000)
998001
(c) 495²
(500 - 5)²
(250000 + 25 - 5000)
245025
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