Question

Find the squares of the following numbers using the identity (a+b)^2 = a^2+2ab+b^2 201 and 111
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Answer 1

Answer:

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Answer 2

510

On decomposing,

⇒ 510 500 + 10

Here, a = 500 andb = 10

Squaring on both sides of equation (1), ⇒ (510)² = (500 + 10)²

= (500)² + 2(500)(10) + (10)² [(a + b) = a ^ 2 + 2ab + b ^ 2]

= 250000 + 10000 + 100

- 260100

.. (510)² = 260100

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