find the squares of the number using the identity:- a) 1001 b) 495 c) 305 d) 99
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#AlexaRousey here!!
We know (a+b) ^2 = a^2 + 2ab + b^2 & (a-b) ^2 = a^2 - 2ab + b^2.
a) 1001^2
= (1000+1)^2
= (1000) ^2 + 2(1000)(1) + 1^2
= 1000000 + 2000 + 1
= 1002001
b) 495^2
=) (500-5)^2
= (500)^2 - 2(500)(5) + 5^2
= 250000 - 5000 + 25
= 245,025
c) 305^2
= (300+5)^2
= (300)^2 + 2(300)(5) + 5^2
= 90000 + 3000 + 25
= 93025
d) 99^2
= (100-1)^2
= (100)^2 - 2(100)(1) + 1^2
= 10000 - 200 + 1
= 9801
Thanks!!
We know (a+b) ^2 = a^2 + 2ab + b^2 & (a-b) ^2 = a^2 - 2ab + b^2.
a) 1001^2
= (1000+1)^2
= (1000) ^2 + 2(1000)(1) + 1^2
= 1000000 + 2000 + 1
= 1002001
b) 495^2
=) (500-5)^2
= (500)^2 - 2(500)(5) + 5^2
= 250000 - 5000 + 25
= 245,025
c) 305^2
= (300+5)^2
= (300)^2 + 2(300)(5) + 5^2
= 90000 + 3000 + 25
= 93025
d) 99^2
= (100-1)^2
= (100)^2 - 2(100)(1) + 1^2
= 10000 - 200 + 1
= 9801
Thanks!!
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