Question

-
Find the squre root of the
following complex number
5 + 12i​

Answer 1

Answer:

Suppose that a+bi is a square root of 5 + 12i. Then, (a+bi)^2 = (a^2 - b^2) + (2ab)i = 5 + 12i. 2ab = 12 ==> b = 6/a. ==> a^4 -5a^2 - 36 = 0