Question

find the squre root of the smallest number divisble by 6,8_15​

Answer 1

Answer:

Let's have a look at the prime factors of these numbers.

6 = 2*3

8 = 2*2*2

15 = 5*3

So any number divisible by these three has to have 2,2,2,3 and 5 as Prime factors. The smallest would be the product of these factors, i.e. 120. However, 120 is not a square.

Now to be a square number, N must have each prime factor occurring an even number of times. So we need another 3 and another 5 as factors. We also need another 2.

So the answer is 2^4 * 3^2 * 5^2 = 3,600.

The square root of 3,600 is 60.

Step-by-step explanation:

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Answer 2

Answer:

hyyy mate

here is your answer.

Step-by-step explanation:

Let's have a look at the prime factor of this number.

6= 2*3

8= 2*2*2

15= 5*3.

so any number divisible by these three has to have 2,2,2,3and 5 as prime factor the smallest would be the product of these factors i.e 120 However 120 is not a square.

Now to be square number N must have each prime factor occurring an even number of times so we need another 3 and another 5 as factor we also need another 2.

so the answer is 2^4*3^2*5^2= 3,600

the square root of 3,600 is 60

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