Find the stationary points of f(x,y)=x^2+y^2+6x+12
and find the Minimum point
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6
Answer:
As a function with 2 variables there is no minimum at any case but a minimum in x and y axis.
So the minimum for x: is d/dx(f(x,y)) (partial) => 2x+6 =0 x=-3 ,
the minimum for y : is d/dy(f(x,y)) (partial) => 2y = 0 => y = 0.
So it is the point (x,y) = (-3,0).
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Answer: (-3,0)
Step-by-step explanation: As a function with 2 variables there may be no minimal at any case however a minimal in x and y axis.
So the minimal for x: is d/dx(f(x,y)) (partial) => 2x+6 =zero x=-3 ,
the minimal for y : is d/dy(f(x,y)) (partial) => 2y = zero => y = zero.
So it's far the point (x,y)
= (-3,zero).
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