Question

Find the step by step answer.
I'll mark Brainliest if I find it proper.​

Answer 1

Hope it is understood...

Answer 2

Step-by-step explanation:

REFER TO THE ATTACHMENT

$cot \: 30 \: = \: \frac{ac}{dc} \\ = > \sqrt{3} = \: \frac{x \: + \: 20}{dc} \\ = > \: dc \: = \frac{ \sqrt{3} (x \: + \: 20)}{3} metres on \: rationalising \: the \: denominator\\ now \\ cot \: 60 \: = \: \frac{x}{ \frac{ \sqrt{3}( \: x \: + \: 20) }{3} } \\ = > \frac{1}{ \sqrt{3} } = \frac{x \: \times \: 3}{ \sqrt{3} ( \: x \: + \: 20)} \\ = > \: 3x \: = x \: + \: 20 \: \\ = > \: 2x \: = 20 \\ = > \: x \: = \: 10 \: metres \: \\ now \: height \: of \: the \: tree \: = \frac{ \sqrt{3}(x \: + \: 20) }{3} \\ = \frac{1.732 \: \times 30}{3} \\ = 17.32 \: metres$

Therefore, breadth of the river = 10 m and height of the tree = 17.32 m